12. Integer to Roman
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Mean:
将一个int型的整数转化为罗马数字.
analyse:
没什么好说的,直接维基百科.
Time complexity: O(N)
view code
/** * ----------------------------------------------------------------- * Copyright (c) 2016 crazyacking.All rights reserved. * ----------------------------------------------------------------- * Author: crazyacking * Date : 2016-02-16-11.55 */ #include <queue> #include <cstdio> #include <set> #include <string> #include <stack> #include <cmath> #include <climits> #include <map> #include <cstdlib> #include <iostream> #include <vector> #include <algorithm> #include <cstring> using namespace std; typedef long long( LL); typedef unsigned long long( ULL); const double eps( 1e-8); class Solution { public : string intToRoman( int num) { string M [] = { "" , "M" , "MM" , "MMM" }; string C [] = { "" , "C" , "CC" , "CCC" , "CD" , "D" , "DC" , "DCC" , "DCCC" , "CM" }; string X [] = { "" , "X" , "XX" , "XXX" , "XL" , "L" , "LX" , "LXX" , "LXXX" , "XC" }; string I [] = { "" , "I" , "II" , "III" , "IV" , "V" , "VI" , "VII" , "VIII" , "IX" }; return M [ num / 1000 ] + C [( num % 1000) / 100 ] + X [( num % 100) / 10 ] + I [ num % 10 ]; } }; int main() { Solution solution; int n; while( cin >>n) { cout << solution . intToRoman(n) << endl; } return 0; }